Below is the syntax highlighted version of AllPaths.java
from §4.5 Case Study: Small World.
/****************************************************************************** * Compilation: javac AllPaths.java * Execution: java AllPaths * Depedencies: Graph.java * * Find all paths from s to t. * * % java AllPaths * A: B C * B: A F * C: A D F * D: C E F G * E: D G * F: B C D * G: D E * * [A, B, F, C, D, E, G] * [A, B, F, C, D, G] * [A, B, F, D, E, G] * [A, B, F, D, G] * [A, C, D, E, G] * [A, C, D, G] * [A, C, F, D, E, G] * [A, C, F, D, G] * * [B, A, C, D, F] * [B, A, C, F] * [B, F] * * Remarks * -------- * - Currently prints in reverse order due to stack toString() * ******************************************************************************/ public class AllPaths<Vertex> { private Stack<String> path = new Stack<String>(); // the current path private SET<String> onPath = new SET<String>(); // the set of vertices on the path public AllPaths(Graph G, String s, String t) { enumerate(G, s, t); } // use DFS private void enumerate(Graph G, String v, String t) { // add node v to current path from s path.push(v); onPath.add(v); // found path from s to t - currently prints in reverse order because of stack if (v.equals(t)) StdOut.println(path); // consider all neighbors that would continue path with repeating a node else { for (String w : G.adjacentTo(v)) { if (!onPath.contains(w)) enumerate(G, w, t); } } // done exploring from v, so remove from path path.pop(); onPath.delete(v); } public static void main(String[] args) { Graph G = new Graph(); G.addEdge("A", "B"); G.addEdge("A", "C"); G.addEdge("C", "D"); G.addEdge("D", "E"); G.addEdge("C", "F"); G.addEdge("B", "F"); G.addEdge("F", "D"); G.addEdge("D", "G"); G.addEdge("E", "G"); StdOut.println(G); new AllPaths(G, "A", "G"); StdOut.println(); new AllPaths(G, "B", "F"); } }