Below is the syntax highlighted version of Diff.java
from §2.3 Recursion.
/****************************************************************************** * Compilation: javac Diff * Execution: java Diff filename1 filename2 * Dependencies: In.java * * Reads in two files and compute their diff. * A bare bones version. * * % java Diff input1.txt input2.txt * * * Limitations * ----------- * - Could hash the lines to avoid potentially more expensive * string comparisons. * ******************************************************************************/ public class Diff { public static void main(String[] args) { // read in lines of each file In in0 = new In(args[0]); In in1 = new In(args[1]); String[] x = in0.readAllLines(); String[] y = in1.readAllLines(); // number of lines of each file int m = x.length; int n = y.length; // opt[i][j] = length of LCS of x[i..m] and y[j..n] int[][] opt = new int[m+1][n+1]; // compute length of LCS and all subproblems via dynamic programming for (int i = m-1; i >= 0; i--) { for (int j = n-1; j >= 0; j--) { if (x[i].equals(y[j])) opt[i][j] = opt[i+1][j+1] + 1; else opt[i][j] = Math.max(opt[i+1][j], opt[i][j+1]); } } // recover LCS itself and print out non-matching lines to standard output int i = 0, j = 0; while (i < m && j < n) { if (x[i].equals(y[j])) { i++; j++; } else if (opt[i+1][j] >= opt[i][j+1]) StdOut.println("< " + x[i++]); else StdOut.println("> " + y[j++]); } // dump out one remainder of one string if the other is exhausted while (i < m || j < n) { if (i == m) StdOut.println("> " + y[j++]); else if (j == n) StdOut.println("< " + x[i++]); } } }