Below is the syntax highlighted version of LongestCommonSubsequence.java
from §2.3 Recursion.
/****************************************************************************** * Compilation: javac LongestCommonSubsequence.java * Execution: java LongestCommonSubsequence s t * ******************************************************************************/ public class LongestCommonSubsequence { // Compute length of LCS for all subproblems. public static String lcs(String x, String y) { int m = x.length(), n = y.length(); int[][] opt = new int[m+1][n+1]; for (int i = m-1; i >= 0; i--) { for (int j = n-1; j >= 0; j--) { if (x.charAt(i) == y.charAt(j)) { opt[i][j] = opt[i+1][j+1] + 1; } else { opt[i][j] = Math.max(opt[i+1][j], opt[i][j+1]); } } } // Recover LCS itself. String lcs = ""; int i = 0, j = 0; while (i < m && j < n) { if (x.charAt(i) == y.charAt(j)) { lcs += x.charAt(i); i++; j++; } else if (opt[i+1][j] >= opt[i][j+1]) i++; else j++; } return lcs; } public static void main(String[] args) { String lcs = lcs(args[0], args[1]); StdOut.println(lcs); } }