Appendix A: Operator Precedence in Java
Java has welldefined rules for specifying the order
in which the operators in an expression are evaluated
when the expression has several operators.
For example, multiplication and division have a higher
precedence than addition and subtraction.
Precedence rules can be overridden by explicit parentheses.
Precedence order.
When two operators share an operand the operator with the higher precedence goes first. For example, 1 + 2 * 3 is treated as 1 + (2 * 3), whereas 1 * 2 + 3 is treated as (1 * 2) + 3 since multiplication has a higher precedence than addition.Associativity.
When an expression has two operators with the same precedence, the expression is evaluated according to its associativity. For example x = y = z = 17 is treated as x = (y = (z = 17)), leaving all three variables with the value 17, since the = operator has righttoleft associativity (and an assignment statement evaluates to the value on the right hand side). On the other hand, 72 / 2 / 3 is treated as (72 / 2) / 3 since the / operator has lefttoright associativity.Precedence and associativity of Java operators.
The table below shows all Java operators from highest to lowest precedence, along with their associativity. Most programmers do not memorize them all, and even those that do still use parentheses for clarity.
Operator  Description  Level  Associativity 

[] . () ++  
access array element access object member invoke a method postincrement postdecrement 
1  left to right 
++  +  ! ~ 
preincrement predecrement unary plus unary minus logical NOT bitwise NOT 
2  right to left 
() new 
cast object creation 
3  right to left 
* / % 
multiplicative  4  left to right 
+  + 
additive string concatenation 
5  left to right 
<< >> >>> 
shift  6  left to right 
< <= > >=instanceof 
relational type comparison 
7  left to right 
== != 
equality  8  left to right 
&  bitwise AND  9  left to right 
^  bitwise XOR  10  left to right 
  bitwise OR  11  left to right 
&&  conditional AND  12  left to right 
  conditional OR  13  left to right 
?:  conditional  14  right to left 
= += = *= /= %= &= ^= = <<= >>= >>>= 
assignment  15  right to left 
There is no explicit operator precedence table in the Java Language Specification and different tables on the web and in textbooks disagree in some minor ways.
Order of evaluation of subexpressions.
Associativity and precedence determine in which order the operators are executed but they do not determine in which order the subexpressions are evaluated. In Java subexpressions are evaluated from left to right. So, for example in the expression A() + B() * C(D(), E()), the functions are evaluated in the order A(), B(), C(), D(), and E(). However, it is considered poor style to write code that relies upon this behavior.Short circuiting. When using the conditional and and or operators (&& and ), Java does not evaluate the second operand unless it is necessary to resolve the result. This allows statements like if (s != null && s.length() < 10) to work reliably. Programmers rarely use the non shortcircuiting versions (& and ) with boolean expressions.
Precedence order gone awry.
Sometimes the precedence order defined in a language do not conform with mathematical norms. For example, in Microsoft Excel, a^b is interpreted as (a)^b instead of (a^b). So 1^2 is equal to 1 instead of 1, which is the values most mathematicians would expect. Microsoft acknowledges this quirk as a "design choice". One wonders whether the programmer was relying on the C precedence order in which unary operators have higher precedence than binary operators. This rule agrees with mathematical conventions for all C operators, but fails with the addition of the exponentiation operator. Once the order was established in Microsoft Excel 2.0, it could not easily be changed without breaking backward compatibility.Exercises.
 What is the result of the following code fragment?
int x = 5; int y = 10; int z = ++x * y;
 What is the result of the following code fragment? Explain.
System.out.println("1 + 2 = " + 1 + 2); System.out.println("1 + 2 = " + (1 + 2));

Add parentheses to the following expression to make the
order of evaluation more clear.
year % 4 == 0 && year % 100 != 0  year % 400 == 0
((year % 4 == 0) && (year % 100 != 0))  (year % 400 == 0)

What does the following code fragment print?
System.out.println(1 + 2 + "abc"); System.out.println("abc" + 1 + 2);
Answer: 3abc and abc12, respectively. The + operator is left associative, whether it is string concatenation or arithmetic plus.